The index of refraction of the core of a piece of fiber optic cable is 1.72.?

If the index of the surrounding cladding is 1.47, what is the critical angle for total internal reflection for a light ray in the core incident on the core-cladding interface?





a) 47 degrees


b) 64.6 degrees


c) 58.7 degrees


d) 52.8 degrees

The index of refraction of the core of a piece of fiber optic cable is 1.72.?
Basically Sin(angle)=n2/n1 = 1.47/1.72 so angle = 58.7 deg (C)

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